Calculate the mass of sodium acetate required to prepare a 100 cm³ solution with a molar concentration of 0.2 mol/dm³

To calculate the mass of sodium acetate (CH3COONa) required to prepare a 100 cm³ solution with a molar concentration of 0.2 mol/dm³, you can use the formula:

$\text{Mass (g)}=\text{Molar Concentration (mol/dm³)}\times \text{Volume (dm³)}\times \text{Molar Mass (g/mol)}$

1. First, you need to find the molar mass of sodium acetate (CH3COONa). You can calculate it by adding the atomic masses of all the atoms in the compound:

   Sodium (Na): 22.99 g/mol
   Carbon (C): 12.01 g/mol
   Hydrogen (H): 1.01 g/mol
   Oxygen (O): 16.00 g/mol

   Molar mass of CH3COONa = (2 x H) + C + (3 x O) + Na
   Molar mass of CH3COONa = (2 x 1.01 g/mol) + 12.01 g/mol + (3 x 16.00 g/mol) + 22.99 g/mol
   Molar mass of CH3COONa = 82.03 g/mol

2. Now, you have the molar mass of sodium acetate, which is 82.03 g/mol.

3. Next, convert the volume of the solution from cm³ to dm³. Since 1 dm³ is equivalent to 1000 cm³, you can divide 100 cm³ by 1000 to get the volume in dm³:

   Volume (dm³) = 100 cm³ / 1000 = 0.1 dm³

4. Now, you have the molar concentration (0.2 mol/dm³), the volume (0.1 dm³), and the molar mass (82.03 g/mol).

5. Plug these values into the formula:

   Mass (g) = 0.2 mol/dm³ x 0.1 dm³ x 82.03 g/mol

6. Calculate the mass:

   Mass (g) = 1.64 g

So, you will need 1.64 grams of sodium acetate to prepare a 100 cm³ solution with a molar concentration of 0.2 mol/dm³.